There's not much to simple combinations with no replacement... if we take the 10 digits from 0 to 9, we can arrange them nearly 4 MILLION ways by using 10!. When we take the subset of squared digits that result in a unique combination of those 10 digits? Now we're down to just 87 numbers n, all of which contain 5 digits.
You could find them all by hand, calculating every squared whole number until you got a value larger than 10 digits (and don't forget, all of them need to be unique), but over 50 years ago the IBM 1620 used its 1,200+ pound frame to work it all out. Do it by hand. What else do you have to do?
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